Use Newton's Law Of Gravity To Compute A 54kg Person's Weight On Mars?

[Thurstun]

F is the force between the masses, G is the gravitational constant, m1 is the first mass, m2 is the second mass, and r is the distance between the centers of the masses.

[Bastion]

Y = ma = Y = H(m1m2)/r^2   Remove algebraically on both sides of daring = signal   a = G(m--Mars)/r^2(mars radius)   I attempted this and got bollixed up, to help you do this comprehending that Mars has 40% planet gravitational speed on area   0.4 * 9.8 m/s^2 = 3.92 m/s^2   Y = 54 kg * 3.92 m/s^2   = 211.68 Newtons/9.8 m/s^2   = 21.6 kg ================phone it 22 kilogram   not necessarily enjoyable, but I'll attempt to return to this.    

[Adonia]

Jenny Craig is in a shirtload of trouble.

[Reg]

F = G Mm /r^2 = 54 kg on earth; Mars M is .107 of Earth's mass, r = .533 times Earth's radius so Mars gravity = .107/.533^2 = .376 times Earth gravity(figures from Wikipedia) 54 x .376 = 20 kg